1/(x-1)+1/x=1/(x^2-x)

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Solution for 1/(x-1)+1/x=1/(x^2-x) equation: 



1/(x-1)+1/x=1/(x^2-x)

We move all terms to the left:

1/(x-1)+1/x-(1/(x^2-x))=0



Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R





Domain of the equation: x!=0

x∈R





Domain of the equation: (x^2-x))!=0

x∈R



We calculate fractions


(x^2*()/((x-1)*x*(x^2-x)))+(1*(x-1)*(x^2-x)))/((x-1)*x*(x^2-x)))+(-(1*(x-1)*x)/((x-1)*x*(x^2-x)))=0



We calculate terms in parentheses: +(x^2*()/((x-1)*x*(x^2-x))), so:

x^2*()/((x-1)*x*(x^2-x))

We multiply all the terms by the denominator


x^2*()

Back to the equation:

+(x^2*())





We calculate terms in parentheses: +(1*(x-1)*(x^2-x)))/((x-1)*x*(x^2-x)))+(-(1*(x-1)*x)/((x-1)*x*(x^2-x))), so:

1*(x-1)*(x^2-x)))/((x-1)*x*(x^2-x)))+(-(1*(x-1)*x)/((x-1)*x*(x^2-x))

We multiply all the terms by the denominator


1*(x-1)*(x^2-x)))-1*x*x^2*((x-x))+(-(1*x*((x-1)*x)-1*x*x^2*((x-x))*((x

We add all the numbers together, and all the variables

1*(x-1)*(x^2-x)))-1*x*x^2*(0)+(-(1*x*((x-1)*x)-1*x*x^2*(0)*((x

We add all the numbers together, and all the variables

1*(x-1)*(x^2-x)))-1*x*x^2*0+(-(1*x*((x-1)*x)-1*x*x^2*0*((x

Wy multiply elements

1*(x-1)*(x^2-x)))-1*x*x^2*0+(-(1*x*((x-1)*x)0*x

Back to the equation:

+(1*(x-1)*(x^2-x)))-1*x*x^2*0+(-(1*x*((x-1)*x)0*x)





We calculate terms in parentheses: +(x^2*()), so:

x^2*()





We calculate terms in parentheses: -(1*x*((x-1)*x)0*x), so:

1*x*((x-1)*x)0*x

Wy multiply elements

x^4*(

We do not support expression: x^4

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